SM-Count wrote:
i delete all the other question since he said he will reuse the test.
ThiefzV2 wrote:#3... u can't simplify it any further. what is the answer?
SM-Count wrote:#3 is the cube root of 3. It was a function analysis question where it indicates 2 verticle asymptotes with no real answers at the outside. Therefore the real answer is just cbet{3}
ThiefzV2 wrote:you are wrong my friend. the given function [(x^3-3)/(x^2-9)] has real values everywhere except when x=-3 and when x=3. an asympotate means there are no solution on the asymptote line, not on the outside. and when an eqn is "simplify" it has to be same as the original eqn. for instance, if u are being asked to simplify (2x/3x) then the answer is (2/3) because no matter what x is then the answer will always be (2/3). Your solution of (3)^(1/3) aka cubert(3) for #3 is not correct because every x you plug in gives you a different answer... not a constant same value. If I am wrong, please teach me the branch of mathematics that u are using and provide me with reference of where i can learn a new system of math.
ThiefzV2 wrote:SM-Count wrote:x^3-3 / x^2-9 has a real answer at the cube root of 3, with asymptotes at 3, -3 and no zeros outside. The phrase simplify in math is a common phrase for finding the zeros, there's no excuse for missing that. If I asked you to simplify a quadratic you would be looking for the zeros, not just giving me the factors, because I asked for the factors. Same thing for this rational function.
Wow just wowi cant believe u just said that.
so the question is when did the word "simplify" means solving for zeroes? Please edumacate me
