Chemistry problem help

[nitrofreez]

So I've gotten some homework for chemistry, and the last question is:

How many molecules (not moles) of NH3 are produced from 6.42×10^−4 g of H2?

Chemical formula: 3H2 (g) + N2 (g)---> 2NH3 (g)

I've been trying this problem for a while but I still can't get it. So,my question is, how would I go about solving this problem? Any help is much appreciated.

-Nitro

EDIT: It's 6.42×10^−4 not 10-4, sorry. Thanks crazy.

[ThiefzV2]

5.56x10^20

[crazyskwrls]

5.56x10^20

i beg to differ, 1.28*10^20


6.42×10−4 g
i guess this is supposed to be 6.42×10^−4 g

[ThiefzV2]

6.42×10−4 g
i guess this is supposed to be 6.42×10^−4 g

yes thats what he meant

5.56x10^20

i beg to differ, 1.28*10^20

No

[nitrofreez]

Incidentally, would you be able to explain to me how you got the answer Crazy? You were right but I'd like to know how you did it for future reference

[crazyskwrls]

6.42×10−4 g
i guess this is supposed to be 6.42×10^−4 g

yes thats what he meant

5.56x10^20

i beg to differ, 1.28*10^20

No

pwned

6.42×10^−4 g
H2 has molar mass of 2
6.42×10^−4 g/2 = 3.21×10^−4 mol of H2

since according to the equation for every 3 mol of H2, 2 mol of NH3 is produced so

3.21×10^−4 mol of H2 * (2/3) = 2.14*10^-4 mol of NH3

avogadro's number is 6.02*10^23

2.14*10^-4 mol of NH3 * 6.02*10^23 = 1.28*10^20

[nitrofreez]

I put in his answer and it came up as correct mate. I tried your answer too but it was wrong.

Thanks, a lot mate. Really appreciate it

[SM-Count]

Crazy has the correct answer but the wrong explanation. You never use H2 to calculate molar mass, you use H with 1g, but the conversion ration 6 moles of hydrogen to 2 moles of ammonia.

[ThiefzV2]

well it was worth a try


crazy, do my HW too plz

[Ashikiheyun]

Lord how I do NOT miss chemistry at all.