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i know how to solve equations like
5x-2y=2
3x+2y=14


But how the hell do you solve this?

v + 2w -x + 2y + z = 2
-v - 2w + x + 2y +3z = 6
2v + 4w -3x + 2y = 3
-3v -6w + 2x + 3z = 9

the question say "Solve v, w, x, y, and z so it satisfies the equations above. There are infinitely many solutions."

i guess substution would work but thats gonna take a while
set up a matrix and solve?

edit
or buy an ti-89 titanium

i'll try later maybe, too lazy

It been a long time since i've done algerbra but dont you use the quadreatic equation to solve those kind of questions?

edit: thats only for 3 unknownss, my bad >_<

tedtwilliger wrote:It been a long time since i've done algerbra but dont you use the quadreatic equation to solve those kind of questions?

demo pl0x?

OOO Your screwed.
That takes a while....

v=-2
w=1
x=-3
y=1
z=1

i did it really quick, didnt even check... wanna check it?

edit forgot z....

the quadratic equation is used only for equations with a squared in one of the x's

example...
f(x)=x^2+2x+5

the quadratic equation is

x=-b+or- square root of b squared -4(a)(c) all divided by 2(a)

OT: lots of substitution would be my guess.... but im to lazy to help you with ur problem.. sry

crazyskwrls wrote:v=-2
w=1
x=-3
y=1
z=1

i did it really quick, didnt even check... wanna check it?

edit forgot z....

sry for double post... but fack you nerd.... xD

M3K0S wrote:

crazyskwrls wrote:v=-2
w=1
x=-3
y=1
z=1

i did it really quick, didnt even check... wanna check it?

edit forgot z....

sry for double post... but fack you nerd.... xD

o well it was completely wrong anyways

Actually I need quick help forgot something.
How do you adda whole number and a fraction?
like

1+ 3/4?

wtf hahah its either 1 3/4 or u make the 1 a fraction which makes it 4/4 + 3/4 then its 7/4

so 1 3/4 or 7/4... ur choice....

M3K0S wrote:

crazyskwrls wrote:v=-2
w=1
x=-3
y=1
z=1

i did it really quick, didnt even check... wanna check it?

edit forgot z....

sry for double post... but fack you nerd.... xD

The solution dont satisify the first question: v + 2w -x + 2y + z = 2

so theres no need to check the remainding eqns

there must be someone that plays SRO that knows how to solve this?

i am a genius

v=-10
w=4
x=-3
y=-1
z=3

How about 2 + 5/9 !

crazyskwrls wrote:i am a genius

v=-10
w=4
x=-3
y=-1
z=3

explaination/show work pl0x or did you do this on your "ti-89 titanium"?

the paper is asking me for 3 possible solutions

Squirt wrote:How about 2 + 5/9 !

same method. I dislike fractions.

2 + 5/9
2/1 + 5/9
2/1(9/9) + 5/9
18/9 + 5/9
23/9

Showed every step so you can understand what I did. Pay attention in class.

Maniac wrote:i know how to solve equations like
5x-2y=2
3x+2y=14


But how the hell do you solve this?

v + 2w -x + 2y + z = 2
-v - 2w + x + 2y +3z = 6
2v + 4w -3x + 2y = 3
-3v -6w + 2x + 3z = 9

the question say "Solve v, w, x, y, and z so it satisfies the equations above. There are infinitely many solutions."

v + 2w -x + 2y + z = 2
-v - 2w + x + 2y +3z = 6
+
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
4y+4z=8

This tell you anything?

Do the same with the 3rd and 4th equation, use the first one get rid of some unknowns.
Notice you can multiply the first one with -2 and 3, and add it with equations 2 and 3.

In the end there will be 3 equations:
4y+4z=8
x-2y=-1
-x+6y+6z=15

Much more easy to solve than the first ones. I got y=-1(lazy to do the rest).
With x y z found use the original equations to get w and v.

Combine like terms

Edit: Nevermind didn't examine the equations.