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need help with this ,not the answer i just want to know how to solve it


the one on the left

If its a linear function, than it means for every x-value, the y-value increases steadily, as opposed to exponentially. Meaning, if you solve it out, each time the x-value in the left box increases by four, you see the y-value increase by two. That would give a a value of 7.

On the right box, you see that each time the x-value increases by 5, the y-value increases by 1. That would give b a value of 5.

So a-b would give you 7-5, which equals 2, or C.

Does that make any sense?

fena wrote:If its a linear function, than it means for every x-value, the y-value increases steadily, as opposed to exponentially. Meaning, if you solve it out, each time the x-value in the left box increases by four, you see the y-value increase by two. That would give a a value of 7.

On the right box, you see that each time the x-value increases by 5, the y-value increases by 1. That would give b a value of 5.

So a-b would give you 7-5, which equals 2, or C.

Does that make any sense?

i makes but in the second one ,x increases by *2 not 5
and i got the same answer but its wrong the answer key said its 4 not 2

it's matter of figuring out how it works.

look well, and you'll see what fena just said.

hemagoku wrote:

fena wrote:If its a linear function, than it means for every x-value, the y-value increases steadily, as opposed to exponentially. Meaning, if you solve it out, each time the x-value in the left box increases by four, you see the y-value increase by two. That would give a a value of 7.

On the right box, you see that each time the x-value increases by 5, the y-value increases by 1. That would give b a value of 5.

So a-b would give you 7-5, which equals 2, or C.

Does that make any sense?

i makes but in the second one ,x increases by *2 not 5
and i got the same answer but its wrong the answer key said its 4 not 2

On the second one, t increases by 5.

Do you see?

5 // 4
10 // 5
15 // 6
20 // 7

The answer key is wrong, lal.

fena wrote:

hemagoku wrote:

fena wrote:If its a linear function, than it means for every x-value, the y-value increases steadily, as opposed to exponentially. Meaning, if you solve it out, each time the x-value in the left box increases by four, you see the y-value increase by two. That would give a a value of 7.

On the right box, you see that each time the x-value increases by 5, the y-value increases by 1. That would give b a value of 5.

So a-b would give you 7-5, which equals 2, or C.

Does that make any sense?

i makes but in the second one ,x increases by *2 not 5
and i got the same answer but its wrong the answer key said its 4 not 2

On the second one, t increases by 5.

Do you see?

5 // 4
10 // 5
15 // 6
20 // 7

The answer key is wrong, lal.

if thats so then thanks cuz i answer 2 and i was mad cuz of the answer key

Where's that from, Hema?
It looks just like the TAKS tests we have to take at the end of each year.

4=5
8=7(a)
12=7


5=4
10=5(b)
20=7

7-5= 2, like fena said, it can't be wrong.

Lol, SATs.

And I'm curious, do you have authorization to use that part of the page on here?

fena wrote:Where's that from, Hema?
It looks just like the TAKS tests we have to take at the end of each year.

its S.A.T .

SM-Count wrote:Lol, SATs.

And I'm curious, do you have authorization to use that part of the page on here?

dunno my mom bought the book yesterday ,and i started using it now and i got this took pic and posted then stopped at problem 14

it's 2...

I hate math.. just skip the lessons mayn!

Yeps its 2.
The answer books we use got so many mistakes that you cant even consider them being [i]real[/u] answer books

sueing you

u cut it (any part) and thats illegal
thanks all ,and mods can close this

For SAT prep, I recommend only using books published by the College Board. I found that the third party books I bought (Sparknotes I think) had many errors in the answer key. The College Board ones are usually made up of old tests, so the answers are 99% correct.

GL

the answer is 2.. If u follow the patter from the right u will solve the question..

f(x)-g(z)
f(8)-g(10)

find slope formula for f(x)...

f(x)=mx+b
solving m
change of y (y2-y1)
over change of x (x2-x1)

5-9 = -4
4-12 = -8
= 4/8=1/2
m=1/2

solving b
y=mx+b
5=1/2(4)+b
5=2+b
3=b

f(x)=y=1/2x+3

find slope formula for g(z)...

g(z)=mx+b
solving m
change of y (y2-y1)
over change of x (x2-x1)

4-7 = -3
5-20 = -15
= 3/15=1/5
m=1/5

solving b
y=mx+b
7=1/5(20)+b
7=4+b
3=b

g(z)=y=1/5z+3

results

first is f(x)=y=1/2x+3
second is g(z)=y=1/5z+3

first x is 8, solve for y [f(x)=f(8)]
second z is 10, solve for y [g(z)=g(10)

DA FIRST
y=1/2(8)+3
y=4+3
y=7

DA SECOND
y=1/5(10)+3
y=2+3
y=5

a-b is
f(x)-g(z)
f(8)-g(10)
7-5
Answer=2

avenqerz wrote:f(x)-g(z)
f(8)-g(10)

find slope formula for f(x)...

f(x)=mx+b
solving m
change of y (y2-y1)
over change of x (x2-x1)

5-9 = -4
4-12 = -8
= 4/8=1/2
m=1/2

solving b
y=mx+b
5=1/2(4)+b
5=2+b
3=b

f(x)=y=1/2x+3

find slope formula for g(z)...

g(z)=mx+b
solving m
change of y (y2-y1)
over change of x (x2-x1)

4-7 = -3
5-20 = -15
= 3/15=1/5
m=1/5

solving b
y=mx+b
7=1/5(20)+b
7=4+b
3=b

g(z)=y=1/5z+3

results

first is f(x)=y=1/2x+3
second is g(z)=y=1/5z+3

first x is 8, solve for y [f(x)=f(8)]
second z is 10, solve for y [g(z)=g(10)

DA FIRST
y=1/2(8)+3
y=4+3
y=7

DA SECOND
y=1/5(10)+3
y=2+3
y=5

a-b is
f(x)-g(z)
f(8)-g(10)
7-5
Answer=2

most helpful post here thanks

avenqerz wrote:f(x)-g(z)
f(8)-g(10)

find slope formula for f(x)...

f(x)=mx+b
solving m
change of y (y2-y1)
over change of x (x2-x1)

5-9 = -4
4-12 = -8
= 4/8=1/2
m=1/2

solving b
y=mx+b
5=1/2(4)+b
5=2+b
3=b

f(x)=y=1/2x+3

find slope formula for g(z)...

g(z)=mx+b
solving m
change of y (y2-y1)
over change of x (x2-x1)

4-7 = -3
5-20 = -15
= 3/15=1/5
m=1/5

solving b
y=mx+b
7=1/5(20)+b
7=4+b
3=b

g(z)=y=1/5z+3

results

first is f(x)=y=1/2x+3
second is g(z)=y=1/5z+3

first x is 8, solve for y [f(x)=f(8)]
second z is 10, solve for y [g(z)=g(10)

DA FIRST
y=1/2(8)+3
y=4+3
y=7

DA SECOND
y=1/5(10)+3
y=2+3
y=5

a-b is
f(x)-g(z)
f(8)-g(10)
7-5
Answer=2

i'm not playing smart or anything but do u really need this formula?
i mean u only need to look at the pattern from the right table and u'll get the missing numbers.