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Quick math problem, help pl0x!
Posted: Sun Nov 11, 2007 9:56 pm
by 0l3n
So, I need a little help.
Find x.
x^2 - 4x + 4 = 9
Could someone help me, shouldnt take more then a few seconds.
Posted: Sun Nov 11, 2007 9:57 pm
by cin
5?
Posted: Sun Nov 11, 2007 9:57 pm
by Itonami
I'm bad at math but i'm trying to figure it out anyways. =X
edit: 6?
Posted: Sun Nov 11, 2007 9:58 pm
by Luoma
i can do it, but someone will post before i get a pen out -.-
we are doing that stuff in school atm
Posted: Sun Nov 11, 2007 9:59 pm
by cin
lol.
5^2 = 25
5*4 = 20
25-20+4=9
so i was right me thinks
Posted: Sun Nov 11, 2007 10:01 pm
by 0l3n
As far as I know this is how you do it, but I think im wrong.
x^2 - 4x + 4 = 9
(x - 4)^2 = 9
x - 4 =+-3
x1= 7
x2= 1
Posted: Sun Nov 11, 2007 10:03 pm
by poehalcho
cin wrote:lol.
5^2 = 25
5*4 = 20
25-20+4=9
so i was right me thinks
what does the ^ do?
Posted: Sun Nov 11, 2007 10:03 pm
by Luoma
0l3n wrote:As far as I know this is how you do it, but I think im wrong.
x^2 - 4x + 4 = 9
(x - 4)^2 = 9
x - 4 =+-3
x1= 7
x2= 1
x1 and x2 should be same number but 1 = + and 2 = -
>.O?
Posted: Sun Nov 11, 2007 10:03 pm
by cin
0l3n wrote:As far as I know this is how you do it, but I think im wrong.
x^2 - 4x + 4 = 9
(x - 4)^2 = 9
x - 4 =+-3
x1= 7
x2= 1
huh O.o
x^2 = x*x
x =/= (x-4)
so how can x^2 be (x-4)^2
Posted: Sun Nov 11, 2007 10:05 pm
by San
-9 from the right
x^2-4X-5=0
then
factor:
(x+1)(x-5)=0
x=-1
x=5
i think

, my algebra brain isnt working after geometry
Posted: Sun Nov 11, 2007 10:14 pm
by 0l3n
San wrote:-9 from the right
x^2-4X-5=0
then simplify:
(x+1)(x-5)=0
x=-1
x=5
i think

, my algebra brain isnt working after geometry
Its the right answer but I dont get it. lol.
where does the"(x+1)" come from?
Posted: Sun Nov 11, 2007 10:17 pm
by StealMySoda
0l3n wrote:As far as I know this is how you do it, but I think im wrong.
x^2 - 4x + 4 = 9
(x - 4)^2 = 9
x - 4 =+-3
x1= 7
x2= 1
49 - 36 + 4 = 17
x=5
x=-5
25 - 20 + 4 = 9
25 - 20 + 4 = 9
I havent actually worked it out, but thats just using trial and error

Posted: Sun Nov 11, 2007 10:25 pm
by pipigrande
This is right 100%

. Just gonna explain it to you by steps i guess.
1) x^2 - 4x + 4 = 9
--> Rearange equation.
x^2 - 4x - 5 = 0
2) Now solve for x.
x^2 - 4x - 5 = 0
(x - 5) (x+1)
3) Now you have got ur x values. x = 5 or x = -1
You can substitus these x values into the equation and see it yourself.
Posted: Sun Nov 11, 2007 10:26 pm
by San
0l3n wrote:San wrote:-9 from the right
x^2-4X-5=0
then simplify:
(x+1)(x-5)=0
x=-1
x=5
i think

, my algebra brain isnt working after geometry
Its the right answer but I dont get it. lol.
where does the"(x+1)" come from?
after subtracting 9, u get X^2-4X-5=0 right?
well, u have to get that to a (X+#)(X-#)=0, which is EDIT: FACTORING!!
so, u take the -4x and -5, and see which 2 numbers multiply to -5 and add to -4, in this case, 1 and -5
so, that fills in to (X+1)(X-5)=0
then u no that u need to multiply something by 0 to get 0, so u take the opposite of any of the #s, in this case, -1 and 5
i dont really no how to explain it very well =.=
the # with an X is the one that the 2 numbers must ADD up to, and the one with out an X is the one they must MULTIPLY to
Posted: Sun Nov 11, 2007 10:26 pm
by pipigrande
StealMySoda wrote:0l3n wrote:As far as I know this is how you do it, but I think im wrong.
x^2 - 4x + 4 = 9
(x - 4)^2 = 9
x - 4 =+-3
x1= 7
x2= 1
49 - 36 + 4 = 17 x=5
x=-5
25 - 20 + 4 = 9
25 - 20 + 4 = 9
I havent actually worked it out, but thats just using trial and error

If you put -5 into the equation, you woulnt get -20, you would get +20.
Posted: Sun Nov 11, 2007 10:27 pm
by cin
time for bed =_=
thnx guys

Posted: Sun Nov 11, 2007 10:29 pm
by Silkroad
0l3n wrote:San wrote:-9 from the right
x^2-4X-5=0
then simplify:
(x+1)(x-5)=0
x=-1
x=5
i think

, my algebra brain isnt working after geometry
Its the right answer but I dont get it. lol.
where does the"(x+1)" come from?
San is right ... it's just simple factoring
Posted: Sun Nov 11, 2007 10:30 pm
by San
cin wrote:time for bed =_=
thnx guys

i thought this was 0l3n's question
why are u thanking us?
lol, i called it oversimplifying
its factoring, thanks silkroad
Posted: Sun Nov 11, 2007 10:31 pm
by cin
San wrote:cin wrote:time for bed =_=
thnx guys

i thought this was 0l3n's question
why are u thanking us?

maths make me sleepy
night night <3
Posted: Sun Nov 11, 2007 10:35 pm
by Aiyas
x = 5
x = -1
Rewrite the equation as x^2 - 4x - 5 = 0.
You can then write the equation as (x - 5)(x + 1) = 0.
So yeah, what San said.
Posted: Sun Nov 11, 2007 10:35 pm
by San
cin wrote:San wrote:cin wrote:time for bed =_=
thnx guys

i thought this was 0l3n's question
why are u thanking us?

maths make me sleepy
night night <3
rest easy cin
i didnt ace algebra for nothing!
Posted: Sun Nov 11, 2007 10:40 pm
by binnosh
this is like 3th grade maths :p
it's kinda easy :p
and it's exactly as san said, he used the rule of horner i think it was to simplify it.
http://www.physics.utah.edu/~detar/less ... node1.html
thats kinda what it does in a nutshell, not really clear tho but just do a lookup of "Rule of Horner" and u'll find buttloads of stuff
Posted: Sun Nov 11, 2007 10:40 pm
by 0l3n
Dont fully understand the (x+1) but I figured it out.
x^2 - 4x + 4 = 9
(x - 2)^2 = 9
x - 2 = +-3
x = 5
x = -1
Posted: Sun Nov 11, 2007 10:48 pm
by StealMySoda
pipigrande wrote:StealMySoda wrote:0l3n wrote:As far as I know this is how you do it, but I think im wrong.
x^2 - 4x + 4 = 9
(x - 4)^2 = 9
x - 4 =+-3
x1= 7
x2= 1
49 - 36 + 4 = 17 x=5
x=-5
25 - 20 + 4 = 9
25 - 20 + 4 = 9
I havent actually worked it out, but thats just using trial and error

If you put -5 into the equation, you woulnt get -20, you would get +20.
DOH xD
Posted: Sun Nov 11, 2007 10:50 pm
by dom
I remember vaguely doing this in grade 9 I think, and i've never had to use it (or almost anything I learned in any of my highschool math classes) since -.-
Posted: Sun Nov 11, 2007 10:59 pm
by Nenhunter
lets see, this is simple factoring. some people already solved it, but i'll explain it:
Problem:
x^2-4x+4=9
set one side equal to 0:
x^2-4x-5=0
factor that equation into 2 binomials:
(x-5)(x+1)=0
solve for each x and thus giving:
x=+5
x=-1
Aiyas has the right answers but didn't explain in detail, but I covered that

Posted: Sun Nov 11, 2007 11:02 pm
by San
Nenhunter wrote:lets see, this is simple factoring. some people already solved it, but i'll explain it:
Problem:
x^2-4x+4=9
set one side equal to 0:
x^2-4x-5=0
factor that equation into 2 binomials:
(x-5)(x+1)=0
solve for each x and thus giving:
x=+5
x=-1
Aiyas has the right answers but didn't explain in detail, but I covered that

ever bother to look at my post
Posted: Sun Nov 11, 2007 11:08 pm
by Sylhana
Yup san already got it right.
But you could arrange it to x^2-4x-5=0, and draw the graph like so...
the answer you are looking for are the x-intercepts 
Posted: Sun Nov 11, 2007 11:15 pm
by CrimsonNuker
Sylhana wrote:Yup san already got it right.
But you could arrange it to x^2-4x-5=0, and draw the graph like so...
the answer you are looking for are the x-intercepts 
Lulz parabola Standard form xD
Posted: Sun Nov 11, 2007 11:19 pm
by San
CrimsonNuker wrote:Sylhana wrote:Yup san already got it right.
But you could arrange it to x^2-4x-5=0, and draw the graph like so...
the answer you are looking for are the x-intercepts 
Lulz parabola Standard form xD
i always pronounced parabol para-bola not paRAbolA
