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Can anyone solve this ???? ~_~


when x = 0 the answer is 4
x= 1 is 5
x=2 is 9
x=3 is 18
x=4 is 34
x=5 is 59
x=6 is 95

its the previous answer + x*x

wait nvm did it wrong lmao too tired

I always hated math,but il try to do it

You're joking, right?

Well i think i got the first...But i dont want look like an idiot... (Only had an C-B in math...)

No,im wrong it cant be... ahh what the hell

woutR wrote:You're joking, right?

well if you mean me then yes...hence the " " face

@ satman you put back the avy hehe ?

TOO......MUCH.....EFFORT
eh I'm not even going to try to solve that lol

I don't even know what you're asking us to find.

Impractical Math is by far my weakest subject.

I will never, ever, use analytical geometry in my life. So sorry bud, can't help you here.

Kitt wrote:Can anyone solve this ???? ~_~


when x = 0 the answer is 4
x= 1 is 5
x=2 is 9
x=3 is 18
x=4 is 34
x=5 is 59
x=6 is 95

its the previous answer + x*x

f(x) = 4 IFF x = 0
f(x) = f(x-1) + x^2 IFF x > 0

amirite?

LuV3r8o1 wrote:

Kitt wrote:Can anyone solve this ???? ~_~


when x = 0 the answer is 4
x= 1 is 5
x=2 is 9
x=3 is 18
x=4 is 34
x=5 is 59
x=6 is 95

its the previous answer + x*x

f(x) = 4 IFF x = 0
f(x) = f(x-1) + x^2 IFF x > 0

amirite?

but if x= 1 then

f(x)= (1-1) +1^2 and that doesn't =5 .....right

also are you allowed to some up with 2 solutions in these problems


Kitt mad me sad today

XemnasXD wrote:

LuV3r8o1 wrote:

Kitt wrote:Can anyone solve this ???? ~_~


when x = 0 the answer is 4
x= 1 is 5
x=2 is 9
x=3 is 18
x=4 is 34
x=5 is 59
x=6 is 95

its the previous answer + x*x

f(x) = 4 IFF x = 0
f(x) = f(x-1) + x^2 IFF x > 0

amirite?

but if x= 1 then

f(x)= (1-1) +1^2 and that doesn't =5 .....right

No. It's recursive.

if x = 1, then
f(x) = f(1-1)+ 1^2
f(x) = f(0) + 1
f(x) = 4 +1
f(x) = 5

since f(x) = 4 when x = 0

XemnasXD wrote:also are you allowed to some up with 2 solutions in these problems

Well, since i assumed it was recursive, I needed a base case. Since you never mentioned negative numbers and i'm too lazy to do the work, I just stopped at f(0) = 4 and didn't worry about negative numbers.

So, the base case is f(0) = 4 and all you have to say is that this function only works for real, positive integers.

But I have no idea what the question to the problem is, so this is all assumption that it solves your problem.

lol

LuV3r8o1 wrote:

XemnasXD wrote:

LuV3r8o1 wrote:

Kitt wrote:Can anyone solve this ???? ~_~


when x = 0 the answer is 4
x= 1 is 5
x=2 is 9
x=3 is 18
x=4 is 34
x=5 is 59
x=6 is 95

its the previous answer + x*x

f(x) = 4 IFF x = 0
f(x) = f(x-1) + x^2 IFF x > 0

amirite?

but if x= 1 then

f(x)= (1-1) +1^2 and that doesn't =5 .....right

No. It's recursive.

if x = 1, then
f(x) = f(1-1)+ 1^2
f(x) = f(0) + 1
f(x) = 4 +1
f(x) = 5

since f(x) = 4 when x = 0

AHHHHHHH your smart!

i get what you are saying now im assuming it works for the other numbahs

now that thats out of the way i can enjoy my life again...

MastaChiefX wrote:Impractical Math is by far my weakest subject.

I will never, ever, use analytical geometry in my life. So sorry bud, can't help you here.

SRF=Part of your life.

lolz thanks guys errm acutally it was a math question my friend asked me to help him with :s and thats all the info he gave me o.O

TO TO TO TOOOOOOOOOOOOOOOOOOOOOOO MUCH MATH

What are you trying to do to me I mean come on it's summer break!!!

LuV3r8o1 wrote:

Kitt wrote:Can anyone solve this ???? ~_~


when x = 0 the answer is 4
x= 1 is 5
x=2 is 9
x=3 is 18
x=4 is 34
x=5 is 59
x=6 is 95

its the previous answer + x*x

f(x) = 4 IFF x = 0
f(x) = f(x-1) + x^2 IFF x > 0

amirite?

uarerite

TwelveEleven wrote:

LuV3r8o1 wrote:

Kitt wrote:Can anyone solve this ???? ~_~


when x = 0 the answer is 4
x= 1 is 5
x=2 is 9
x=3 is 18
x=4 is 34
x=5 is 59
x=6 is 95

its the previous answer + x*x

f(x) = 4 IFF x = 0
f(x) = f(x-1) + x^2 IFF x > 0

amirite?

uarerite

kthxbi