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(0.625T)╥(0.0250m)^2 *cosine of angle x = 1.00*10^-4 T*m^2
Solve for x

This came out of my physics textbook, so I already know the answer is 85.3 degrees; however, I do not know how to do algebra with trigonometric functions. If someone could just show me how to rewrite this, it would help me a lot.

Is that really the right answer? and question?
I keep getting 1.489 wth

aznronin wrote:Is that really the right answer? and question?
I keep getting 1.489 wth

The answer is right, but I may have typed the question wrong...

The formula for magnetic flux is

Φ = BA cos θ

B=0.625T
A=pi*radius^2 since this is the area of a loop. The radius is 0.0250m.

The question is "At what angle is the flux in this system equal to 1.00*10^-4 T*m^2?"

These are all just silly symbols in random order

the f*ck is dis shit

I'd help, but we haven't learned this yet in my physics class.

I hate this class

Seji wrote:the f*ck is dis shit

indeed

aznronin wrote:Is that really the right answer? and question?
I keep getting 1.489 wth

You do know 1.489 radians is 85.3 degrees right?

SM-Count wrote:

aznronin wrote:Is that really the right answer? and question?
I keep getting 1.489 wth

You do know 1.489 radians is 85.3 degrees right?

LMFAO... you sir win...

I was wondering if they converted or not...

ok, can someone show me step by step, how to do it now? lol

ur probably thinking way too hard

SM-Count wrote:
ur probably thinking way too hard

thank you very much!

Dam it, I thought I knew the answer, but I was missing one thing... dam senior year giving me regular calculus!