Silkroad Online Forums

Just having fun.

x(x-x)=0

(x-x)(x+x)=0

x(x-x)=(x-x)(x+x)
x=x+x
Let x=1
1=1+1
1=2

Someones gotta win a cookie.
(Just found it funny that my entire Calc AP class, excluding the teacher, couldn't get it ^ ^)

...what?

Mr.Ganji wrote:...what?

Does 1=2?

the first step is false

Mr.Ganji wrote:the first step is false

x(x-x)=x²-x²=0

The first step is correct.

Nantosh wrote:Just having fun.

x(x-x)=0

(x-x)(x+x)=0

x(x-x)=(x-x)(x+x)
x=x+x
Let x=1
1=1+1
1=2

Someones gotta win a cookie.
(Just found it funny that my entire Calc AP class, excluding the teacher, couldn't get it ^ ^)

ummm wut

x(x-x)=0 say x = 1
1(1-1)=1(0)=0
(x-x)(x+x)=0 say x =1
(1-1)(1+1)=(o)(2)=0
x(x-x)=(x-x)(x+x)say x = 1
1(1-1)=(1-1)(1+1)
1(0)=(0)(2)
0=0

i understand how it works but saying x=1 means you can solve the whole thing so you don't need x=x+x

Lady_Shadows wrote:

Nantosh wrote:Just having fun.

x(x-x)=0

(x-x)(x+x)=0

x(x-x)=(x-x)(x+x)
x=x+x
Let x=1
1=1+1
1=2

Someones gotta win a cookie.
(Just found it funny that my entire Calc AP class, excluding the teacher, couldn't get it ^ ^)

ummm wut

x(x-x)=0 say x = 1
1(1-1)=1(0)=0
(x-x)(x+x)=0 say x =1
(1-1)(1+1)=(o)(2)=0
x(x-x)=(x-x)(x+x)say x = 1
1(1-1)=(1-1)(1+1)
1(0)=(0)(2)
0=0

i understand how it works but saying x=1 means you can solve the whole thing so you don't need x=x+x

Correct, if you plug in 1 in the start. However, working algebraically with the variables results in a different answer. I'm looking to see if anyone can point out the deviation in the original work provided.

Nantosh wrote:

Lady_Shadows wrote:

Nantosh wrote:Just having fun.

x(x-x)=0

(x-x)(x+x)=0

x(x-x)=(x-x)(x+x)
x=x+x
Let x=1
1=1+1
1=2

Someones gotta win a cookie.
(Just found it funny that my entire Calc AP class, excluding the teacher, couldn't get it ^ ^)

ummm wut

x(x-x)=0 say x = 1
1(1-1)=1(0)=0
(x-x)(x+x)=0 say x =1
(1-1)(1+1)=(o)(2)=0
x(x-x)=(x-x)(x+x)say x = 1
1(1-1)=(1-1)(1+1)
1(0)=(0)(2)
0=0

i understand how it works but saying x=1 means you can solve the whole thing so you don't need x=x+x

Correct, if you plug in 1 in the start. However, working algebraically with the variables results in a different answer. I'm looking to see if anyone can point out the deviation in the original work provided.

its simple (x-x) cancels each other out
x(x-x)=(x-x)(x+x)
-(x-x)
x=x+x
if x = 1 then 1=1+1

Nantosh wrote:Just having fun.

x(x-x)=0

(x-x)(x+x)=0

x(x-x)=(x-x)(x+x)
x=x+x
Let x=1
1=1+1
1=2

I dont think you can go backwards...
x(x-x)=0
x²-x²=0 ( How do you know [x²-x²=0] = [(x-x)(x+x)=0] )
(x-x)(x+x)=0
-------------------------
Only forward...idk just guessing here, my brain isn't even functioning right now.
(x-x)(x+x)=0
x²-x²=0
x(x-x)=0

Keep trying.
So far all you've found is that there is, in fact, a problem.
Your looking for the cause.

Problem?

Shomari wrote:

Code: Select all

x(x-x)=(x-x)(x+x)
x=x+x

Problem?

Understanding certain nuances on the webz can be difficult.
Response: How so?

Nantosh wrote:

Shomari wrote:

Code: Select all

x(x-x)=(x-x)(x+x)
x=x+x

Problem?

Understanding certain nuances on the webz can be difficult.
Response: How so?

How does:
x(x-x) = x
If you said x(x-x)=0

Shomari wrote:

Nantosh wrote:

Shomari wrote:

Code: Select all

x(x-x)=(x-x)(x+x)
x=x+x

Problem?

Understanding certain nuances on the webz can be difficult.
Response: How so?

How does:
x(x-x) = x
If you said x(x-x)=0

Divide by (x-x).

Nantosh wrote:Divide by (x-x).

Well if (x-x)=0
Then you are dividing by 0 which is not possible.

Shomari wrote:

Nantosh wrote:Divide by (x-x).

Well if (x-x)=0
Then you are dividing by 0 which is not possible.

Win. Thanks.
And graduated or not?

Only the 6th time this has come up, I'll give you a cookie for being original.

Nantosh wrote:

Shomari wrote:

Nantosh wrote:Divide by (x-x).

Well if (x-x)=0
Then you are dividing by 0 which is not possible.

Win. Thanks.
And graduated or not?

Nope.

SM-Count wrote:Only the 6th time this has come up, I'll give you a cookie for being original.

Heh, oh well. I was just seeing how easily crackable this was, and thus how stupid my class was.

Thanks Shomari ^ ^

Nantosh wrote:

SM-Count wrote:Only the 6th time this has come up, I'll give you a cookie for being original.

Heh, oh well. I was just seeing how easily crackable this was, and thus how stupid my class was.

Thanks Shomari ^ ^

Lol no problem

want a cookie? Here is where you'll get it viewtopic.php?f=12&t=98038

and I thought my maths was bad

NuclearSilo wrote:want a cookie? Here is where you'll get it viewtopic.php?f=12&t=98038

bump there