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Chocolate Math
Posted: Fri Apr 10, 2009 7:56 pm
by Mr.Ganji
From an email
Don't tell me your age; you probably would tell a falsehood anyway
-but the Hershey Man will know! YOUR AGE BY CHOCOLATE MATH
This is pretty neat.
DON'T CHEAT BY SCROLLING DOWN FIRST!
It takes less than a minute .
Work this out as you read ..
Be sure you don't read the bottom until you've worked it out!
This is not one of those waste of time things, it's fun.
1. First of all, pick the number of times a week that you would like to have chocolate (more than once but less than 10)
2. Multiply this number by 2 (just to be bold)
3. Add 5
4. Multiply it by 50 -- I'll wait while you get the calculator
5. If you have already had your birthday this year add 1759 ...
If you haven't, add 1758.
6. Now subtract the four digit year that you were born.
You should have a three digit number
The first digit of this was your original number
(i.e., how many times you want to have chocolate each week).
The next two numbers are
YOUR AGE! (Oh YES, it is!!!!!)
THIS IS THE ONLY YEAR (2009) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS.
chocolate Calculator.
Re: Chocolate Math
Posted: Fri Apr 10, 2009 8:01 pm
by woutR
It had the times of chocolate per week correct, but not my age.
I'm 17 and it said I was 18.
Re: Chocolate Math
Posted: Fri Apr 10, 2009 8:20 pm
by C1ockwork
It said I was one year older than I am as well.
Re: Chocolate Math
Posted: Fri Apr 10, 2009 8:27 pm
by Psychedeelic
lol it worked for me
Re: Chocolate Math
Posted: Fri Apr 10, 2009 8:28 pm
by JoyFax
Worked for me
Re: Chocolate Math
Posted: Fri Apr 10, 2009 8:30 pm
by Furious
it worked for me

Re: Chocolate Math
Posted: Fri Apr 10, 2009 8:41 pm
by Squirt
Cool trick.
Re: Chocolate Math
Posted: Fri Apr 10, 2009 10:13 pm
by Azilius
Worked..I remember we had to make these up in math class

Re: Chocolate Math
Posted: Sat Apr 11, 2009 2:16 am
by FireVortex
sweet it was rite
Re: Chocolate Math
Posted: Sat Apr 11, 2009 2:27 am
by Crowley
Shit son. It worked.
Re: Chocolate Math
Posted: Sat Apr 11, 2009 2:57 am
by nohunta
Any mathmatecians care to explain why it worked?
Re: Chocolate Math
Posted: Sat Apr 11, 2009 3:06 am
by thaosterpro
thats funny.

Re: Chocolate Math
Posted: Sat Apr 11, 2009 9:38 am
by XMoshe
Worked here too.
Re: Chocolate Math
Posted: Sat Apr 11, 2009 9:59 am
by *BlackFox
Yeah! It worked!
Re: Chocolate Math
Posted: Sat Apr 11, 2009 10:03 am
by DotCom
((2*x + 5)* 50 + 1759) - yearOfBday
=(100*x + 250 + 1759) - yearOfBday
=100*x + 2009 - yearOfBday
=100*x + yourAge
Math always works!
Re: Chocolate Math
Posted: Sat Apr 11, 2009 11:26 am
by only_me
nohunta wrote:Any mathmatecians care to explain why it worked?
so u take a random number ( it can be even bigger than 10 , it still works

)
when multiply a number by 2 is always a even number

and when u +5 that even number u get a odd number
when u multiply a odd number by 5 it will always end in a 5
(in our case is 50 but the only difference is that our number will end in 50

)
let's say that u pick 3
[(3*2)+5]*50 = 550
or let's say u pick 7
[(7*2)+5]*50 = 950
or let's say u pick 1
[(1*2)+5]*50 = 350
now here is the trick :
the number 1759(or 1758) makes all the magic
u can notice that 1759 + 250 = 2009 ( our actual year )
* or 1758 + 250 = 2008 ( if u haven't had your birthday this year )
and if u do 2009(or 2008 , depending on the case) - "your birth year" u will find your age
and 1759 + 350 = 2009 + 100 = 2109
2109 - "your birth year" = 100 + your age

= 1"your age" ( 1 is the number of "chocolates" )
Re: Chocolate Math
Posted: Sat Apr 11, 2009 11:38 am
by Mameluke
only_me wrote:nohunta wrote:Any mathmatecians care to explain why it worked?
so u take a random number ( it can be even bigger than 10 , it still works

)
when multiply a number by 2 is always a even number

and when u +5 that even number u get a odd number
when u multiply a odd number by 5 it will always end in a 5
(in our case is 50 but the only difference is that our number will end in 50

)
let's say that u pick 3
[(3*2)+5]*50 = 550
or let's say u pick 7
[(7*2)+5]*50 = 950
or let's say u pick 1
[(1*2)+5]*50 = 350
now here is the trick :
the number 1759(or 1758) makes all the magic
u can notice that 1759 + 250 = 2009 ( our actual year )
* or 1758 + 250 = 2008 ( if u haven't had your birthday this year )
and if u do 2009(or 2008 , depending on the case) - "your birth year" u will find your age
and 1759 + 350 = 2009 + 100 = 2109
2109 - "your birth year" = 100 + your age

= 1"your age" ( 1 is the number of "chocolates" )
basically what DotCom already said but more complicated...